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More Posts from Fade-22 and Others

3 years ago
Europe Is In Danger

europe is in danger


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1 year ago

Ice cream bread - 1978

3 years ago

whenever you post online, just imagine how your grandma would react if she read it.; and then how you would feel if she promptly died and your post was the last thing she ever read


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10 months ago

Hi I only dare to ask on anon, but why are you so awesome?

You forgot to turn on anon.

1 year ago

you ever heard a lightning fucking scream?

youre about to

1 year ago

Y’ever read something and have understanding that has eluded you interminably suddenly stop, curl up, and snuggle neatly into a fold in your brain because a new way way opened to it?

Y’ever Read Something And Have Understanding That Has Eluded You Interminably Suddenly Stop, Curl Up,
1 year ago

i am not joking we need to force teach cooking in schools. like. it is an essential thing for survival. do you know how easy it is to make things if you know even the bare bones shit about how cooking works. we need to teach teenagers how far you can take an onion and some other veggies it''s sad that people grow up not knowing how to prepare literally anything. and i'm not talking about oh this home ed class taught me how to make chicken nuggets at home i'm talking about learning the balancing of sweetness and acidity and saltiness and bitterness and shit like that and techniques and oil temperatures and how meats cook. it needs to be taught because it's literally not even that difficult and it matters so much

1 year ago
This Image Hurts My Brain More Than The Original Debate Ever Did. Brains Are Dumb.

This image hurts my brain more than the original debate ever did. Brains are dumb.

1 year ago

P(A)=Number of favorable outcomesTotal number of possible outcomesP(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}P(A)=Total number of possible outcomesNumber of favorable outcomes​

P(A′)=1−P(A)P(A') = 1 - P(A)P(A′)=1−P(A)

P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)

P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)P(A∪B)=P(A)+P(B)−P(A∩B)

P(A∣B)=P(A∩B)P(B)P(A | B) = \frac{P(A \cap B)}{P(B)}P(A∣B)=P(B)P(A∩B)​

P(A∩B)=P(A)⋅P(B)P(A \cap B) = P(A) \cdot P(B)P(A∩B)=P(A)⋅P(B)

P(A∩B)=P(A)⋅P(B∣A)P(A \cap B) = P(A) \cdot P(B | A)P(A∩B)=P(A)⋅P(B∣A)

P(A∣B)=P(B∣A)⋅P(A)P(B)P(A | B) = \frac{P(B | A) \cdot P(A)}{P(B)}P(A∣B)=P(B)P(B∣A)⋅P(A)​

P(A)=∑i=1nP(A∣Bi)⋅P(Bi)P(A) = \sum_{i=1}^{n} P(A | B_i) \cdot P(B_i)P(A)=∑i=1n​P(A∣Bi​)⋅P(Bi​)

p(x)p(x)p(x): E(X)=∑xx⋅p(x)E(X) = \sum_{x} x \cdot p(x)E(X)=∑x​x⋅p(x)

Var(X)=E(X2)−[E(X)]2\text{Var}(X) = E(X^2) - [E(X)]^2Var(X)=E(X2)−[E(X)]2

σX=Var(X)\sigma_X = \sqrt{\text{Var}(X)}σX​=Var(X)​

P(X=k)=(nk)pk(1−p)n−kP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}P(X=k)=(kn​)pk(1−p)n−k where (nk)=n!k!(n−k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}(kn​)=k!(n−k)!n!​

P(X=k)=λke−λk!P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!}P(X=k)=k!λke−λ​

f(x)=1σ2πe−(x−μ)22σ2f(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{(x-\mu)^2}{2\sigma^2}}f(x)=σ2π​1​e−2σ2(x−μ)2​

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